End of paper
(if loads are independent, DF ~1.2) But here, conveyor and HVAC may run together → use 1.1. Adjusted MD_kW = ( 55.31 / 1.1 = 50.28 , kW) maximum demand calculation 3 phase
Load Name | kW | PF | kVA | Demand Factor | Coincident kW | Coincident kVA ----------|----|----|-----|---------------|---------------|--------------- ... | | | | | | Total coincident kW = _______ Weighted PF = _______ MD_kVA = Total coincident kW / PF = _______ Add margin (____ %) = _______ Selected MD = ______ kVA End of paper (if loads are independent, DF ~1
Weighted PF = Total kW / Total kVA without diversity? Compute: Compute: kVA per load (without diversity): Lighting: 10/0
kVA per load (without diversity): Lighting: 10/0.9 = 11.11 Sockets: 15/0.8 = 18.75 Conveyor: 23.91/0.85 = 28.13 Welder: 30 kVA (given) ×0.3 duty = 9 kVA HVAC: 18/0.8 = 22.5 Sum kVA = 11.11+18.75+28.13+9+22.5 = 89.49 kVA Sum kW = 10+15+23.91+5.4+18 = 72.31 kW (note: welder active 5.4, not 30) Weighted PF = 72.31/89.49 = 0.808
MD_kVA = 50.28 / 0.808 = 62.23 kVA
If welder connected to L1‑L2, and conveyor on L2‑L3, the peak phase might be L2. For final design, balance loads.